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Start your free trialLarry Singleton
18,946 PointsASP.NET MVC Basics
I can't see where I'm going wrong, I followed the video several times...
Link: https://teamtreehouse.com/library/aspnet-mvc-basics/views/displaying-a-list-of-values
Question:
Using the Razor syntax, write the characters string array variable value to the view within the provided <ul> element.
Use a foreach loop to render each characters string array value within its own <li> element.
Name your loop value variable character.
Be sure to remove the placeholder <!-- characters --> HTML comments.
My failing answer:
@{
Layout = null;
var title = "Super Mario 64";
var description = "Super Mario 64 is a 1996 platform video game developed and published by Nintendo for the Nintendo 64.";
var characters = new string[]
{
"Mario",
"Princess Peach",
"Bowser",
"Toad",
"Yoshi"
};
}
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width" />
<title>Video Game Detail</title>
</head>
<body>
<div>
<h1>@title</h1>
<h5>Description:</h5>
<div>@description</div>
@if (characters.Length > 0)
{
<h5>Characters:</h5>
<div>
<ul>
@foreach(var character in characters)
{
<li>@characters</li>
}
</ul>
</div>
}
</div>
</body>
</html>
This is just one variation of my attempts.
@{
Layout = null;
var title = "Super Mario 64";
var description = "Super Mario 64 is a 1996 platform video game developed and published by Nintendo for the Nintendo 64.";
var characters = new string[]
{
"Mario",
"Princess Peach",
"Bowser",
"Toad",
"Yoshi"
};
}
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width" />
<title>Video Game Detail</title>
</head>
<body>
<div>
<h1>@title</h1>
<h5>Description:</h5>
<div>@description</div>
@if (characters.Length > 0)
{
<h5>Characters:</h5>
<div>
<ul>
@foreach(var character in characters)
{
<li>@characters</li>
}
</ul>
</div>
}
</div>
</body>
</html>
2 Answers
Steven Parker
231,248 PointsHi, I got your request to answer.
It looks like you have the wrong name .. or maybe just a typo.
Your loop is correct, but when you render the item within the <li>
tags, you call it "characters" (the whole array) instead of "character" (the individual item).
Just remove that "s" and you'll pass!
Larry Singleton
18,946 PointsI did, I get the following error:
Bummer! Did you remove any of the provided markup?
Steven Parker
231,248 PointsOh, it looks like you did too much. You should only replace the "<!-- characters -->
" line with the loop that generates the <li>
's. Don't make any other changes (like adding that "@if...
" line).