Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialSylvia Pan
7,093 PointsAbout regex...
Hey, guys, I've been stuck at this point with the compiler telling me I got '1234567890'. I think I've excluded 5, 6, and 7. Can someone tell me where is the problem?
import re
string = '1234567890'
good_numbers = re.findall(r'[\d]*[^5-7]',string)
1 Answer
Maxim Andreev
24,529 Pointsgood_numbers = re.findall(r'[^567]', string)
edit: Just to explain, if you have [\d]* in front it will look for any combination of numbers [0-9]* followed by any character except 5,6 or 7.