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Java Java Basics Getting Started with Java IO

Posted by Unsubscribed User
Unsubscribed User
800 Points

Add a variable to store a user’s first name using console.readLine. Make sure the variable is the camel cased representa

it keeps telling me to use camelCased and it is. what am i doing wrong

IO.java 
// I have imported java.io.Console for you.  It is a variable called console.
console.readLine("firstName  ");

2 Answers

Steve Hunter
Steve Hunter
57,712 Points
Steve Hunter
Steve Hunter
57,712 Points

As Dan says, you need to store a name in a variable named with camelCase convention.

So, you're storing a string, so it shoud be delcared as such and this string will hold the input of the console.readLine command.

Something like:

String firstName = console.readLine("Dave");

The value "Dave" will then be stored in firstName.

Dan Johnson
Dan Johnson
40,533 Points
Dan Johnson
Dan Johnson
40,533 Points

If you were to call

String firstName = console.readLine("Dave");

This will present the user with the text "Dave" before their input. firstName will contain whatever was typed in after the prompt, and before a newline was encountered.

Oracle docs: http://docs.oracle.com/javase/7/docs/api/java/io/Console.html#readLine%28java.lang.String,%20java.lang.Object...%29

Steve Hunter
Steve Hunter
57,712 Points

Sorry, I'm talking nonsense - Dan, thankfully, isn't!! :-)

Dan Johnson
Dan Johnson
40,533 Points
Dan Johnson
Dan Johnson
40,533 Points

No worries, just didn't want any confusion over the String argument.

Dan Johnson
Dan Johnson
40,533 Points
Dan Johnson
Dan Johnson
40,533 Points

The string passed into readLine is the prompt to the user. The return value from readLine is what contains the input and what you'll want to set a String variable (with the name of firstName as you had) to.