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Python Python Basics Functions and Looping While Loops

Abdullah Jassim
Abdullah Jassim
4,551 Points
Posted by Abdullah Jassim
Abdullah Jassim
4,551 Points

After the first attempt, I dont see the message - you have made 1 attempt. I only see if after second attempt. Guidance?

import sys

master_password = "opensesame"
password = input("Enter the password ")
attempt = 0


while password != master_password:
    if attempt < 3:
        password = input("Invalid password. Try again. ")
        attempt += 1
        print("You have made {} out of 3 attempts".format(attempt))
    else:
        sys.exit("Too many attempts")

print("Welcome to secret world")

1 Answer

Grigorij Schleifer
Grigorij Schleifer
10,365 Points
Grigorij Schleifer
Grigorij Schleifer
10,365 Points

Hi Abdullah,

I reordered your version and would suggest this approach.

import sys

master_password = "opensesame"
password = input("Enter the password ")
attempt = 0


while password != master_password:
    if attempt < 3: # you should increase the attempt count before the print statement
        attempt += 1
        print("You have made {} out of 3 attempts".format(attempt))  # print the updated count
        password = input("Invalid password. Try again. ")
    else:
        sys.exit("Too many attempts") # if the user tries to log in more than three times the program is stoped

print("Welcome to secret world")

What do you think?