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Start your free trialGary Beardsley
1,403 PointsAm I supposed to do an if/else for both variable names? I tried to append the sentence to the name variable,didn't work.
I tried to append the name variable to the sentence required previously but it didn't work. I'm not sure how I am supposed to answer this correctly. In the way I've done it this time I tried to make the $studentOneName = the string required because it says change the variable to display "NAME made 4.0 GPA", not sure what I'm doing incorrectly. I put the alternative version in the comment block at the bottom.
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;
$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;
//Place your code below this comment
if($studentOneGPA == 4.0) {
$studentOneName = "Dave made the Honor Roll\n";
echo $studentOneName;
} else {
$studentOneName = "Dave has a GPA of $studentOneGPA\n";
echo $studentOneName;
}
if($studentTwoGPA == 4.0) {
$studentTwoName = "Treasure made the Honor Roll\n";
echo $studentTwoName;
} else {
$studentTwoName = "Treasure has a GPA of $studentTwoGPA\n";
echo $studentTwoName;
}
/*
alternatively:
$studentOneName = 'Dave';
$studentOneGPA = 3.8;
$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;
if($studentOneGPA == 4.0) {
echo $studentOneName . "made the Honor Roll\n";
} else {
echo $studentOneName . " has a GPA of " . $studentOneGPA . "\n";
}
if($studentTwoGPA == 4.0) {
$studentTwoName = "Treasure made the Honor Roll\n";
echo $studentTwoName;
} else {
$studentTwoName = "Treasure has a GPA of $studentTwoGPA\n";
echo $studentTwoName;
}
*/
?>
1 Answer
Justin Kraft
26,327 PointsHi Gary,
Your first if/else block in the commented alternative section you have posted is the correct format that is looked for. When I checked the assignment I initially left of the new line characters and it was accepted so I'm not sure if it will accept it with them or not. If you repeat the below for the second student you should be able to progress.
if($studentOneGPA == 4.0) {
echo $studentOneName . "made the Honor Roll";
} else {
echo $studentOneName . " has a GPA of " . $studentOneGPA;
}
Gary Beardsley
1,403 PointsGary Beardsley
1,403 PointsThank you, it worked!