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Start your free trialMaciek Stępniewski
1,082 Pointsbreak out of loop // halp
whyyyyy
def loopy(items):
for xoxo in items:
print(xoxo)
if xoxo == "STOP":
break
3 Answers
Steven Parker
231,271 PointsYour test is not part of the loop. Anything that is in the body of a loop must be indented more than the "for" line itself. And a "break" statement is only allowed inside a loop.
Also, the test and break should be performed before the print or the word "STOP" will be printed out as a list item.
I'll bet you can get it from here without an explicit code spoiler.
Patrick Bluth
13,285 PointsHey there!
You made a very small mistake. Your If statement is actually outside your for loop! Your If statement will only be read once your for loop is completed. You need to add the extra white space before your If statement to ensure that it is contained within your loop. This will ensure that for every item in the items list will be checked to see if it is equal to "STOP".
Also, we want to break out of the loop when the item is "STOP", but we want to do this BEFORE we print that item. This means the break statement must come before the print statement.
Reformatting like so should fix your code:
def loopy(items):
for item in items:
if item == "STOP":
break
print(item)
I hope that helps.
Maciek Stępniewski
1,082 PointsI like you both quite much.