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Start your free trialEugene Shepherd
826 PointsC# I cannot understand why the code does not work
Ok this is the basic course of c# the final task.
We've updated our previous CheckSpeed method to return a string value. Update the method body with this logic:
If the speed parameter is over 65, return the string "too fast". If the speed parameter is under 45, return the string "too slow". Otherwise, return the string "speed OK".
I cannot understand why it wont accept my solution since it works fine on visual basic 2019 My solution is as follows
using System;
class Program {
static string CheckSpeed(double speed)
{
if (speed > 65)
{
Console.WriteLine("too fast.");
}
else if (speed < 45)
{
Console.WriteLine("too slow.");
}
else
{
Console.WriteLine("speed ok.");
}
return Convert.ToString(speed);
}
static void Main(string[] args)
{
// This should print "too slow".
Console.WriteLine(CheckSpeed(44));
// This should print "too fast".
Console.WriteLine(CheckSpeed(88));
// This should print "speed OK".
Console.WriteLine(CheckSpeed(55));
}
}
The error I get from that code is Bummer: too fast. We called CheckSpeed(65.5), but we got a return value of: "65.5". We were expecting "too fast".
Eugene Shepherd
826 PointsAh yes, thank you guys. I just needed to return the strings directly. Much appreciated!!
1 Answer
Steven Parker
231,248 PointsThere seems to be 3 issues:
- the function should not return the speed itself
- the function should return the messages instead of writing them our (the main modules does that)
- the messages should be exactly as given in the instructions, no added punctuation or case changes
Jesรบs Armenta
13,505 PointsJesรบs Armenta
13,505 PointsYour program works fine but the instruction given was to return just the message not the conversion of the speed parameter in the end, so just return the message instead of Console.WriteLine in the if/else statements.