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Python Introducing Lists Build an Application Multidimensional Musical Groups

Posted by Bryan Davila
Bryan Davila
3,966 Points

Cannot output all groups

In this code, I can get the for loop to output a single item in the list by calling it by the index number but, if I remove the specific index number, I get the error that there was a string expected but instead a list was found. How can I fix to output all the groups separated by the ", ".join ?

groups.py 
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
# Your code here

for members in musical_groups:
    all_members = ", ".join(musical_groups)
    print(all_members) 
    break

2 Answers

Clayton Perszyk
MOD
Clayton Perszyk
Treehouse Moderator 48,850 Points
Clayton Perszyk
Clayton Perszyk
Treehouse Moderator 48,850 Points

You are passing the wrong argument to join and you need to remove break

Bryan Davila
Bryan Davila
3,966 Points
Bryan Davila
Bryan Davila
3,966 Points

Thank you, Clayton. I passed through 'members' instead and got the right output.