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Python Python Basics (2015) Shopping List App Break

Posted by Panos Amelides
Panos Amelides
426 Points

Cannot pass Task 2 of 2

def loopy(items): # Code goes here for item in items: print(item) if item == "STOP": break

what am I doing wrong here???

breaks.py 
def loopy(items):
    # Code goes here
    for item in items:
        print(item)
        if item == "STOP":
            break

3 Answers

Steven Parker
Steven Parker
231,271 Points
Steven Parker
Steven Parker
231,271 Points

If you don't want "STOP" to be printed out, the test and break should be done before the print.

Panos Amelides
Panos Amelides
426 Points
Panos Amelides
Panos Amelides
426 Points

Thanks Steven. I need to break out of the loop when the current item is the string "STOP".

I tried this:

def loopy(items): # Code goes here if item == "STOP" break for item in items: print(item)

but again I got an error and not sure why.

Steven Parker
Steven Parker
231,271 Points
Steven Parker
Steven Parker
231,271 Points

The test needs to be inside the loop, just before the print (you moved it one line too far back).

Panos Amelides
Panos Amelides
426 Points
Panos Amelides
Panos Amelides
426 Points

Thanks Steven, I made it right after I sent you my 2nd reply. :-)