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Start your free trialJonas Støvring
5,229 PointsCant seem to call the right function in this task
Bummer! It doesn't look like you've called the get_flavor function. Please check your code and try again - this is the error message I receive :) Can anyone help me.
<?php
include("flavor.php");
$flavor = "get_flavor";
echo "Hal's favorite flavor of ice cream is $flavor.";
?>
1 Answer
Don Macarthur
28,430 PointsHi Jonas,
You have a couple of issues.
Firstly, you are not calling the function get_flavor correctly. Calling a function in PHP requires you to enter the name of the function followed by parentheses. i.e. To call the get_flavor function you would write get_flavor(), and without the quotation marks surrounding them as you currently have
The second part is as Jesse mentions above, you need to concatenate the $flavor variable outside of the string. Don't forget to also concatenate the period at the end of the sentence otherwise it won't pass. i.e. something like
"This is my string " . $variable . ".";
Hope that helps. Don :-)
Jesse Rushlow
Courses Plus Student 2,828 PointsJesse Rushlow
Courses Plus Student 2,828 PointsIt's been a while since I've used php but it looks like you need to separate your variable $flavor from the string in your echo statement.
I.e. echo "Heres my string and my " . $var;