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Start your free trialOliver Bird
57,653 PointsChanging a users password - " Bummer! Make the $newPassword and $verifyNewPassword are the same."
I've tested this locally and it seems to work.
Not sure if I have misunderstood, however I don't see any mention of the $verifyNewPassword variable in the initial question.
<?php
function newPasswordValid($userPassword, $currPassword, $newPassword, $confirmNewPassword) {
//add code here
if (password_verify($currPassword, $userPassword)) {
if ($newPassword === $confirmNewPassword) {
try {
$hashedPassword = password_hash($newPassword, PASSWORD_DEFAULT);
return $hashedPassword;
} catch (\Exception $e) {
return false;
}
}
}
}
1 Answer
Tomas Svojanovsky
26,680 PointsHello, look at the documentation. Any of these methods doesn't return exception, so try catch is useless. Your solution returns null if if doesn't valid.
My opinion: I think better solution would be return null if passwords are not valid, otherwise return hash. Then I would use return type ?string and php forces me type return null, so you can easily avoid this.
http://php.net/manual/en/function.password-hash.php http://php.net/manual/en/function.password-verify.php
I did it like this:
<?php
function newPasswordValid($userPassword, $currPassword, $newPassword, $confirmNewPassword) {
//add code here
if (password_verify($currPassword, $userPassword) && $newPassword === $confirmNewPassword) {
return password_hash($newPassword, PASSWORD_DEFAULT);
}
return false;
}
Oliver Bird
57,653 PointsOliver Bird
57,653 PointsThank you. Makes more sense now!