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Start your free trialRaju Kolte
3,110 Pointsconfusing in arrguments
Hello team im new in php my question is what is the connection both of this $arr & $names when we call them we use $names but the first argument is $arr what they can connect each other... im confuse
4 Answers
Jacob Mishkin
23,118 Points$arr is a parameter. Its a placeholder in the function. At the end of the video $names is the array that is done like so:
<? php
$names = array(
'Hampton',
'Mike',
'Charley'
);
?>
the relationship of $names and $arr is that, $arr is a parameter for the function. Think of it as a variable for the function ONLY We then call the function with the $names variable like in the video. By calling the function with the $names variable we are able to echo the names above.
Presley Cobb
9,214 PointsIf you could show the code you are talking about that would be great. But if the names of the variables are different then they are separate. You should not think of them as connected if they are declared normally. Normally meaning $var = "placeholder text";
Matthew Brock
16,791 Points// the video uses $name first and expects it to be a string.
function hello($name)
// then it shows using $arr as the variable for the function.
function hello($arr)
// It then uses the if statement to check to see if it is an array.
if (is_array($arr)) { // checks to see if is an array
foreach($arr as $name) {
// this loops through every item in the array and gives you the value $name
// so first time through loop would be "Hampton"
// then next time would be "Mike"
}
} else { // is something other than array
}
Presley Cobb
9,214 PointsThere is no difference in the way the variables are used. $arr and $name are used in the exact same way here. He just changed how he named the variable. Now what may be confusing you is that he creates an array called name and then passes the variable into the function. Basically just ignore the first example that where he creates a function called hello with $name as a parameter.
Focus on the second example. What he is doing is instead of passing a single value into the function he is passing an array of values. The name of that array is called $name. He should have used 3 different variable names because I can see how it would be confusing the way it was done.