Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialSantiago Cabrera
11,087 PointsDon't understand why it doesn't work
Nothing
var expect = require('chai').expect
describe('subtraction', function () {
var subtraction = require('../WHEREVER')
it('only works with numbers', function () {
// YOUR CODE HERE
expect(subtraction.subtraction()).to.throw(Error);
})
})
function subtraction (number1, number2) {
if (typeof number1 !== 'number' || typeof number2 !== 'number') {
throw Error('subtraction only works with numbers!')
}
return number1 - number2
}
1 Answer
Tim Gavlick
11,725 Points2 things:
We apparently don't need to call "subtraction.subtraction()". "subtraction()" works just fine.
expect, in this case, is looking for a callable function and not the result of calling the function.
expect(subtraction('a', 'b'))
won't give Chai the chance to catch the exception, but giving it a callable function will. This can be done via the wrapper method in the previous video, or by passing a bound or anonymous function into expect; e.g.
expect(subtraction.bind(null, 'a', 'b'))