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Omar Hussien Khafagy
1,431 Pointsfizz buzz challenge.py
name = input("Please enter your name: ")
number = int(input(("Please enter a number: "))
print("hello" , name,"your number is" , number)
if number =(%3==0):
print("is a Fizz number.")
elif number = (%5==0):
print("is a Buzz number.")
elif number =(%3==0 and %5==0):
print("is a FizzBuzz number.")
else number=(%3!=0 and %5!=0):
print("is neither a fizzy or a buzzy number.")
plz help to fix this code !!
[MOD: added ```python formatting -cf]
2 Answers
Chris Freeman
Treehouse Moderator 68,454 PointsYou have the correct idea. Some syntax to fix up:
- There's an extra open paren "(" in line 2
- The modulo syntax is
if number % 3 == 0:orif number % 3 == 0 and number % 5 == 0: - The last
elsehas a conditional, so it should be anelifinstead
That should do it. Post back if you need more help. Good luck!!
Omar Hussien Khafagy
1,431 PointsI am sorry Second note. I didn't pay attention to it I removed the mark = So are the parentheses. thank you for help
Chris Freeman
Treehouse Moderator 68,454 PointsChris Freeman
Treehouse Moderator 68,454 PointsThere is one additional fix. The order of the
ifstatements need adjusting. Try "15", it should be a FizzBuzz but it gets called a Fizz. Can you see the issue?