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Python Functions, Packing, and Unpacking Getting Info In and Out of Functions Functions with Arguments and Returns

functions with arguments and returns

This doesn't make complete sense to me; Can I get a little help please

creating_functions.py
def hello_student(name):
    'Ashley' != 'Hello Ashley'
    return 'Hello Ashley'

1 Answer

You have created a function named hello_student that has a parameter named name and returns Hello Ashley

def hello_student(name):
    'Ashley' != 'Hello Ashley'
    return 'Hello Ashley'

You can call the function and print the results as follows

print(hello_student("Keegan")) 

and the output is

Hello Ashley

You can store the result of the function in a variable

hello = hello_student("Bob")

and print the result

print(hello)

and the output is still

Hello Ashley

The challenge wants you to return 'Hello ' followed by the value of the name passed in. You can do this with concatenation. This allows you to pass in different names and achieve different results.

return 'Hello ' + name

In between this you have this line:

 'Ashley' != 'Hello Ashley'

Is there a reason for this? What do you think this line does? If you remove this line and modify the return statement

def hello_student(name):
    return 'Hello ' + name

You can then call the function and print the result

print(hello_student("Keegan")) 

and the output is

Hello Keegan

Or store the result of the function in a variable

hello = hello_student("Bob")

and print the result

print(hello)

and the output is

Hello Bob