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Start your free trialKeegan Swanson
1,339 Pointsfunctions with arguments and returns
This doesn't make complete sense to me; Can I get a little help please
def hello_student(name):
'Ashley' != 'Hello Ashley'
return 'Hello Ashley'
1 Answer
KRIS NIKOLAISEN
54,971 PointsYou have created a function named hello_student
that has a parameter named name
and returns Hello Ashley
def hello_student(name):
'Ashley' != 'Hello Ashley'
return 'Hello Ashley'
You can call the function and print the results as follows
print(hello_student("Keegan"))
and the output is
Hello Ashley
You can store the result of the function in a variable
hello = hello_student("Bob")
and print the result
print(hello)
and the output is still
Hello Ashley
The challenge wants you to return 'Hello ' followed by the value of the name passed in. You can do this with concatenation. This allows you to pass in different names and achieve different results.
return 'Hello ' + name
In between this you have this line:
'Ashley' != 'Hello Ashley'
Is there a reason for this? What do you think this line does? If you remove this line and modify the return statement
def hello_student(name):
return 'Hello ' + name
You can then call the function and print the result
print(hello_student("Keegan"))
and the output is
Hello Keegan
Or store the result of the function in a variable
hello = hello_student("Bob")
and print the result
print(hello)
and the output is
Hello Bob