Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Jeffrey SPICHER
Front End Web Development Techdegree Student 7,548 PointsHello why does my code tells me : here is your nan number between 1 and four instead of you have to pick a number?
// Collect input from a user
const userNumber = prompt('Pick a number'); console.log(userNumber);
// Convert the input to a number
const UserInNumber = parseInt(userNumber); console.log(UserInNumber);
// Use Math.random() and the user's number to generate a random number
if (userNumber) {
const UserRandomNumber = Math.floor(Math.random() * UserInNumber) + 1;
// Create a message displaying the random number
document.querySelector ('main').innerHTML =
<h1>Here is your random number ${UserRandomNumber} between 1 and ${userNumber}</h1>;
} else { document.querySelector ('main').innerHTML = '<h1>You have to pick a number</h1>';
}
2 Answers
Cameron Childres
11,820 PointsHi Jeffrey,
This is because you're using the variable userNumber as the condition for your if statement. Since userNumber is defined with a prompt it will always return a string, which is considered "truthy". There are two exceptions: if you click "cancel" on the prompt it will return null, or if you click "okay" without anything entered it will return an empty string, which are both falsy and will execute your else statement.
If you change the condition to UserInNumber instead you'll be checking the result of parseInt() which will return NaN for strings and 0, executing your else statement. You'll want to change userNumber to UserInNumber in the template literal as well or you could end up with messages containing things like "..and 3.75" or "..and 52cats" instead of an integer.
One last tip -- check out the "markdown cheatsheet" linked below the comment box for help with formatting your code on the forum, it will make it easier to read and prevent characters from being dropped like the backticks around your template literal.
Jeffrey SPICHER
Front End Web Development Techdegree Student 7,548 PointsThank you very much !