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JavaScript AJAX Basics AJAX Concepts Finish the AJAX Request

Posted by Alexandru Pescaru
Alexandru Pescaru
6,410 Points

hi guys. So i written the code that i think is correct and variable xhr is not good....

can anyone help me please

app.js 
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
};
xhr.open('GET', 'footer.html');
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="footer"></div>
</body>
</html>

1 Answer

Jeff Muday
MOD
Jeff Muday
Treehouse Moderator 28,720 Points
Jeff Muday
Jeff Muday
Treehouse Moderator 28,720 Points

The variable xhr is not declared. You need to use the request variable instead.

var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
};
request.open('GET', 'footer.html');
Alexandru Pescaru
Alexandru Pescaru
6,410 Points

thx!