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Start your free trialAurelius Calliste {Callicodes}
8,196 PointsHi there I'm inputting the following for this question: const hiddenitems = $('li:hidden'); hiddenitems.show() ????
There are three hidden items on this page-- a div and two list items. Use jQuery's :hidden pseudo selector to select only the hidden list items. Then use the show() method to expose the hidden elements.
<!DOCTYPE html>
<html lang="en">
<head>
<title>Document</title>
<link rel="stylesheet" href="style.css" type="text/css" media="screen" title="no title" charset="utf-8">
</head>
<body>
<h2>Star Trek Characters</h2>
<ul class="character-list">
<li>Captain Jean Luc Picard</li>
<li>Data</li>
<li>Warf</li>
<li>Dr. Crusher</li>
</ul>
<div>I am supposed to stay hidden!</div>
<script
src="jquery-3.2.1.min.js"></script>
<script src="app.js"></script>
</body>
</html>
const hiddenitems = $('li:hidden');
hiddenitems.show()
1 Answer
Sahil Kapoor
8,932 PointsYou are doing absolutely correct just don't put " $("li:hidden") " into any variable. Just use it like the below code.
$("li:hidden").show();
Assigning the li elements to variable is the only mistake and its not actually a mistake its just that the interpreter produces error.
Aurelius Calliste {Callicodes}
8,196 PointsAurelius Calliste {Callicodes}
8,196 PointsMuch respect Sahil... appreciate that.