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Naison Masiyashe
2,736 Pointshow do i do it
this is the message i am getting on this code challeng: " It looks like you called the right function but you aren't loading the return value into a variable with the name . Your code should look something like this: $variable = function_name()" am not getting what i should be doing here
<?php
include 'flavor.php';
get_flavor([$flavor=null ]);
echo "Hal's favorite flavor of ice cream is ____.";
?>
1 Answer
Jennifer Nordell
Treehouse TeacherThe get_flavor function takes no arguments and returns a value ( in this case a string containing a flavor of ice cream). Take a look at what you need:
<?php
include 'flavor.php';
$flavor = get_flavor();
echo "Hal's favorite flavor of ice cream is ____.";
?>
Here we set up our flavor variable then tell it to go into the flavor.php file and run the get_flavor() function. We know that it will return a string containing an ice cream flavor, but have no idea which one. So it does that and returns the string which is now stored (appropriately enough) in our $flavor variable. Hope this helps!