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tejaswini vadnal
1,587 Pointshow to add
Next, we need the flavor selected in the dropdown to be submitted to this process.php file. We need to be able to access it in the "flavor" element of the $_POST array, like this: $_POST["flavor"]. Change the HTML so that the value for "flavor" is submitted to the process.php file. (Hint. An "id" attribute on a form input can be used by JavaScript and CSS but is not passed through the form submission.
<!DOCTYPE html>
<html>
<head>
<title>Ye Olde Ice Cream Shoppe</title>
</head>
<body>
<p>Your order has been created. What flavor of ice cream would you like to add to it?</p>
<form method="post" action="process.php">
<table>
<tr>
<th></th>
<td></td>
</tr>
</table>
<label for="flavor">Flavor</label>
<select id="flavor">
<option value="">— Select —</option>
<option value="Vanilla">Vanilla</option>
<option value="Chocolate">Chocolate</option>
<option value="Strawberry">Strawberry</option>
<option value="Cookie Dough">Cookie Dough</option>
</select>
<input type="submit" value="Update Order">
</form>
</body>
</html>
2 Answers
Veronica Rivera
32,599 PointsYour code should look like this
<select id="flavor" name="flavor">
Pauline Orr
15,321 PointsHey!
What you need to do is add name="flavor" to your select element. Hope this helps.