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Start your free trialmark babyby
Full Stack JavaScript Techdegree Student 367 PointsHow to add super to add_item method
class Inventory: def init(self): self.slots = []
def add_item(self, item):
self.slots.append(item)
class SortedInventory(Inventory): def add_item(self, item): super().add_item(self,item): pass
class Inventory:
def __init__(self):
self.slots = []
def add_item(self, item):
self.slots.append(item)
class SortedInventory(Inventory):
def add_item(self, item):
super().add_item(self,item):
pass
1 Answer
Steven Parker
231,271 PointsYou're close, but:
- when you call the super's "add_item", you don't need to pass "self" as an argument
- the line calling the super's "add_item" should not have a colon at the end
- you don't need "pass" anymore now that you have a method
mark babyby
Full Stack JavaScript Techdegree Student 367 Pointsmark babyby
Full Stack JavaScript Techdegree Student 367 PointsThank you for your helpful answer but why don't we need to pass self as an argument in super
Jonathan Grieve
Treehouse Moderator 91,253 PointsJonathan Grieve
Treehouse Moderator 91,253 PointsHere's a link that may shed some light on that for you.
https://www.codecademy.com/forum_questions/547e29f79c4e9d958e0049db
https://stackoverflow.com/questions/36557009/explicit-passing-of-self-when-calling-super-classs-init-in-python
It's not required to pass the self parameter when calling super(). My understanding of this is that if you don't want to refer to the parent class, you wouldn't pass self to super.
Steven Parker
231,271 PointsSteven Parker
231,271 PointsIt's just like any other method call, you don't explicitly pass "self", but the system provides it to the method as the first parameter implicitly.
mark babyby
Full Stack JavaScript Techdegree Student 367 Pointsmark babyby
Full Stack JavaScript Techdegree Student 367 Pointsthank you