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Start your free trialSirin Srikier
7,671 PointsI am getting this error Warning: Invalid argument supplied for foreach() in /home/treehouse/workspace/catalog.php
I checked and rechecked the code and I don't know where I went wrong.
<div class="section catalog page"> <div class="wrapper"> <h1><?php echo $pageTitle; ?></h1> <ul class="items"> <?php $categories = array_category($catalog,$section);
foreach($categories as $id) {
echo get_item_html($id,$catalog[$id]);
} ?> </ul> </div>
2 Answers
Lindsey Somerset
10,592 PointsI got the same error statement! Check the array_category function. On catalog.php, I did a var_dump() to the page like this:
<?php
$categories = array_category($catalog, $section);
var_dump($categories);
When on the Full Catalog section, it printed that it was an empty array. When I clicked on the books, movies, and music links; the var_dump() printed that it was an integer! I went to the array_category function and realized I was missing the square brackets from this line:
<?php
$output[] = $id;
Without the square brackets, a catalog id number was being assigned to $output. That would return an error in the foreach loop because it doesn't accept a number type as an arguments. Apparently I missed the part when she added those square brackets. Hope this helps!
Matthew Bilz
15,829 PointsI don't believe that array_category is a built in PHP function - unless it's included in a function you have already built? Try using just a normal array in your 'foreach' and that error message shouldn't come up anymore.
Lindsey Somerset
10,592 PointsIn the tutorial, we created the array_category function and included it from another file.
Nick Dim
12,885 PointsNick Dim
12,885 PointsThat's exactly what my mistake was. I did a var_dump and realized that $output wasn't adding the $id's just assigned the last one
Aurelien Roux
25,567 PointsAurelien Roux
25,567 PointsThank you Lindsey!!!
John Driscoll
20,782 PointsJohn Driscoll
20,782 PointsThank you, this answer helped me out. I made the exact same mistake.