Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript Exit Out of the Loop – One Solution

I don't understand this path, perhaps you can help

here's my code:

const main = document.querySelector('main');
const randomNumber = 10;
let guess;
let attempts = 0;

do {

  guess = prompt("What's the number?")  
  attempts++
} while(parseInt(guess) !== randomNumber || attempts < 10);

main.innerHTML = `It took you ${attempts} attempts to guess number ${randomNumber}`;

Now, when it comes to this part - while(parseInt(guess) !== randomNumber || attempts < 10)

it's supposed to work, like a user either does 10 guesses and then gets the message or he guesses the right answer and the message pops up.

Why do i need to use if else function here?

1 Answer

Rohald van Merode
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Rohald van Merode
Treehouse Staff

Hey Cool Beans 👋

Your code should definitely work in terms of breaking out of the loop! As always in coding there are a lot of different ways to accomplish something and the solution shown in the video is just one of them. Your solution seems perfectly valid to me too 😃

The only difference between your code and Guils solution is the messaging to the user if they fail to guess the number within 10 attempts.

Hope this clears things up! 🙂