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Start your free trialGena Israel
2,047 Pointsi dont understand why the answer is trish
Given the code below, what appears in the alert dialogue when this program runs?
var name = "Trish"; function setName() { var name = "Sarah"; } setName(); alert(name);
1 Answer
Steven Parker
231,271 PointsThis question tests your knowledge of "function scope".
According to the rules of function scope, any variable declared within a function is only available to that function. So when the function setName() is invoked, a new variable called "name" is created inside the function and set to "Sarah", but when the function ends, that variable can no longer be accessed by the main program.
But the original global variable "name" can be accessed and still contains the value "Trish".