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JavaScript Introducing the Practice

I feel proud after the Math exercise

After like 3 hours I did the math exercise and I would like to show it with you, I feel very proud because I did it without watching the teacher's solution, just checking in MDN and other sites. I leave the results here and I'll go to see the solution, I hope the solution it is the same as my code, it shows into the screen as the teacher ask/show.

alert('Let\'s do some Math!');

var num1 = prompt('Pick a number'); parseInt(num1); var numb2 = prompt('Please, pick another!'); parseInt(numb2); var message = num1 + numb2; var message = "<h1> Let's do some math with the numbers " + num1 + " and " + numb2 + ".</h1>"; document.write(message);

var result = parseInt(num1) + parseInt(numb2); var result1 = parseInt(num1) * parseInt(numb2); var result2 = parseInt(num1) / parseInt(numb2); var result3 = parseInt(num1) - parseInt(numb2);

document.write(" " + num1 + " + " + numb2 + " = " + result + '<br>');
document.write(" " + num1 + " * " + numb2 + " = " + result1 + '<br>'); document.write(" " + num1 + " / " + numb2 + " = " + result2 + '<br>'); document.write(" " + num1 + " - " + numb2 + " = " + result3 + '<br>');

2 Answers

Steven Parker
Steven Parker
231,271 Points

Good job overall. :+1: But "parseInt" does not change the argument, it only passes back the number value. So "parseInt(numb2);" doesn't do anything by itself, it needs to be assigned to something or used in an expression (as you did later in the code).

Hi Steve! Thanks for your reply! I see what you mean, so applying parseInt at the end of the code as you mention, will run perfectly. To be honest I made so many changes that I got dizzy in a moment haha. Thanks again for your time and your advice :)