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Start your free trialKatie Shook
12,326 PointsI keep getting an unexpected end of input.
I must have something different than Dave does. Anyone have a moment to take a look and see what is causing my unexpected end of input. It says it is on the last line xhr.send(); This is what is showing in the videos so I'm not sure whats happening. I'm sure its something simple. Thanks everyone.
var xhr = new XMLHttpRequest(); xhr.onreadystatechange = function () { if(xhr.readyState === 4 && xhr.status === 200) { var employees = JSON.parse(xhr.responseText); var statusHTML = '<ul class="bulleted">'; for (var i=0; i<employees.length; i += 1) { if (employees[i].inoffice === true) { statusHTML += '<li class="in">'; } else { statusHTML += '<li class="out">'; } statusHTML += employees[i].name; statusHTML += '</li>'; } statusHTML += '</ul>'; document.getElementById('employeeList').innerHTML = statusHTML; } }; xhr.open('GET', '../data/employees.json'); xhr.send();
3 Answers
KRIS NIKOLAISEN
54,971 PointsThere is a missing bracket in the snapshot. There should be two closing brackets before xhr.open()
: one for the if statement if(xhr.readyState === 4 )
and one for the function. If you click a bracket you can see it will highlight along with its match.
}
};
xhr.open('GET', 'data/employees.json');
xhr.send();
Katie Shook
12,326 PointsI should have done that in the first place! Whoops! Here it is! https://w.trhou.se/la8avak0h6
Katie Shook
12,326 PointsAh I must have deleted them on accident. Thank you!!
KRIS NIKOLAISEN
54,971 PointsKRIS NIKOLAISEN
54,971 PointsUsually this is due to a missing bracket but I don't see one in what you posted. It would be easier to tell if you formatted your code using markdown. But I tested your code in the video's workspace and it ran without error.
If you are using a workspace can you post a snapshot? Click the camera icon in the upper right corner, then take snapshot, then post the link created here.