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PHP PHP Basics Daily Exercise Program Conditionals

Nikola Simic
Nikola Simic
2,143 Points
Posted by Nikola Simic
Nikola Simic
2,143 Points

"Incorrect output"

officially clueless

index.php 
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment


if ($studentOneGPA == 4.0) {
  echo "$studentOneName made the Honor Roll\n";
} else {
  echo "$studentOneName has a $studentOneGPA of STUDENT GPA\n" ;
}

if ($studentTwoGPA == 4.0) {
  echo "$studentTwoName made the Honor Roll\n";
} else {
  echo "$studentTwoName has a $studentTwoGPA of STUDENT GPA\n";
}

?>

2 Answers

Dave StSomeWhere
Dave StSomeWhere
19,870 Points
Dave StSomeWhere
Dave StSomeWhere
19,870 Points

Please check the instructions again

If the students GPA is not equal to 4.0, within an else block, use the student name variable to replace NAME AND the student GPA variable to replace STUDENT GPA when displaying the following line: NAME has a GPA of STUDENT GPA

You are supposed to use the variable in place of "STUDENT GPA" not "GPA"

So the line should read:

<?php
echo $studentTwoName  . 'has a GPA of' . $studentTwoGPA;
?>
Tim Knight
Tim Knight
28,888 Points
Tim Knight
Tim Knight
28,888 Points

You're really close Nikola. You'll want to make sure you're concatenating your variables into the message string. To concatenate PHP you'd use the . (period) character. Then just make sure the output message is exactly what they're looking for. Here's an example of concatenating in PHP that should help.

<?php 
    $name = "Nikola";
    $language = "PHP";

    echo $name . " is learning " . $language;
?>