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Start your free trialAndy McDonald
Python Development Techdegree Graduate 13,801 PointsIs a variable with a single letter Truthy?
Still having trouble with this quiz question. My for loop seems to be going but not adding to newword after it becomes what I think is truthy.
backwards = [
'tac',
'esuoheerT',
'htenneK',
[5, 4, 3, 2, 1],
]
def reverse(arg):
letlist = []
for char in arg:
letlist.append(char)
newword = None
count = len(letlist)
for i in range(count - 1, -1, -1):
print('i =' + str(i))
if newword:
newword + letlist[i]
else:
newword = letlist[i]
return newword
print(reverse('words'))
1 Answer
jb30
44,806 PointsA letter is truthy.
The line newword + letlist[i]
does not change the value of newword
. You could try newword += letlist[i]
.
With that change, your program would correctly reverse string inputs such as 'tac'
. However, if you pass in [5, 4, 3, 2, 1]
, you will instead get 15, which is the sum of the array, and if you pass in ['t', 'a', 'c']
, you will get 'cat'
rather than ['c', 'a', 't']
.