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Start your free trialLeonardo Motta
11,284 PointsIs it the desired result of throw new Error?
Not sure if I got it right when we use the throw new Error, our program will stop no matter what? so the user won't be able to continue using it? is that really desired result? I would like to notice the user there was a problem with one of the value and then continue the program with the other values that are right
function getRandomNumber( lower, upper ) {
if (lower < upper) {
return Math.floor(Math.random() * (upper - lower + 1)) + lower;
} else if (lower > upper) {
var temp = lower;
lower = upper;
upper = temp;
return Math.floor(Math.random() * (upper - lower + 1)) + lower;
} else if (isNaN(lower) || isNaN(upper)) {
throw new Error('One of the values is not a number');
}
}
console.log( getRandomNumber( 1, 'five' ) );
console.log( getRandomNumber( 1, 10 ) );
console.log( getRandomNumber( 30, 21 ) );
1 Answer
Steven Parker
231,271 PointsThrowing the error to alert you of the problem allows you to fix the program so all output will be right.
But as you continue in the courses, you'll learn of a mechanism called try...catch that will allow you to respond to a "throw" but to also keep the program running. Click on the link if you'd like to dive into the documentation, or just keep plugging and you'll find out about it soon in the videos.
Leonardo Motta
11,284 PointsLeonardo Motta
11,284 PointsWell, thank you for your answer, sometimes we just want to know that! dint know about this and that I would find more about this later, thanks