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Start your free trialSam Donaghy-Bell
2,670 PointsIs there such a thing as a wrong execution..?
Below is my code. It seemed to do exactly what his did but looks nothing like it. Am I wrong or just not efficient enough yet?
function randomNumber(number1, number2) { return number1, number2; }
var one = (Math.floor(Math.random() * (30000 - 1 + 1)) + 1); var two = (Math.floor(Math.random() * (400000 - 1 + 1)) + 1);
alert(randomNumber(one, two));
1 Answer
Steven Parker
231,271 PointsYou've created the same end result but with code having a different intent.
The intention of the code in the video is to create a function that will return a random number, and then use that function in the body of the code.
But you created a function that only reflects one of it's arguments, and created a random number in the body of the code which you passed through the function (you actually created two, but one of them is simply discarded).
So while the final output may seem the same, what the programs actually do is very different. This would become apparent if the program were to be extended with additional code that called the same function and expected it to return a random number in the provided range.