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JavaScript One Solution

Posted by Uche Onuekwusi
Uche Onuekwusi
18,070 Points

My code is not working

$("#addNew").on("click", function(e){

const inputs = $("#newRestaurant").val(); $("ul").append(inputs);

});

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,971 Points

Could you provide this as a snapshot? It is the camera icon in the upper right corner.

2 Answers

Mark Warren
Mark Warren
19,252 Points
Mark Warren
Mark Warren
19,252 Points

Hi Uche,

You have an unnecessary parameter 'e' in function(e).

Try:

$("#addNew").on("click", function(){

const inputs = $("#newRestaurant").val(); $("ul").append(inputs);

});

Daniel Phillips
Daniel Phillips
26,940 Points
Daniel Phillips
Daniel Phillips
26,940 Points

The input that you are taking the value of has an id="newRestaurantInput", you are selecting $("#newRestaurant") (missing the 'Input' part at the end).