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Start your free trialAmir F
9,095 PointsMy solutions with template literals and unary plus
// declare program variables
let num1;
let num2;
let message;
// announce the program
alert("Let's do some math!");
// collect numeric input and convert into numbers
num1 = prompt("Please type a number");
num1 = +num1;
num2 = prompt("Please type another number");
num2 = +num2;
if (num2 === 0) {
alert("The second number is 0. You can't divide by zero. Reload and try again.");
} else if (Number.isNaN(num1) || Number.isNaN(num2)) {
alert("At least one of the values you typed is not a number. Reload and try again.");
} else {
// build an HTML message
message = `
<h1>Math with the numbers ${num1} and ${num2}</h1>
${num1} + ${num2} = ${num1 + num2} <br>
${num1} * ${num2} = ${num1 * num2} <br>
${num1} / ${num2} = ${num1 / num2} <br>
${num1} - ${num2} = ${num1 - num2}
`
// write message to web page
document.write(message);
}
1 Answer
Steven Parker
231,248 PointsThe template literals are a nice enhancement, but be aware that a unary plus is not an exact replacement for "parseInt". For example, an empty string will produce NaN (not a number) with "parseInt", but a unary plus will convert it to 0.
Amir F
9,095 PointsAmir F
9,095 PointsTrue. I used unary plus to not allow for inputs like "123abc" which converts to 123 with
parseInt()
butNaN
with unary plus.Thanks for the feedback :)