Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Kylie Soderblom
3,890 PointsNeed a 2nd pair of eyes. No errors on console. But no widget list is created.
`var xhr = new XMLHttpRequest(); xhr.onreadystatechange = function () { if(xhr.readyState ===4){ var employees = JSON.parse(xhr.responseText); var statusHTML = '<ul class = "bulleted">'; for(var i= 0; i < employees.length; i++){ if(employees[i].inoffice === true){ statusHTML += '<li class = "in">'; }else{ statusHTML += '<li class = "out">'; } statusHTML += employees[i].name; statusHTML += '</li>'; } statusHTML +='</ul>'; document.getElementById("employeeList").innerHTML = statusHTML; } };
xhr.open("GET", "data/employees.json"); xhr.send();`
1 Answer
Remigiusz Szostak
7,827 Pointseverything should be ok but you need to remove these ```characters at the end and begining because they are reason why your code is treated like a string ('template literal $[expression])
therefore it does not show errors in the console