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Start your free trialAbe Layee
8,378 PointsNEED HELP
I am trying to print out the user id in the url, but I keep getting this error "syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting '-' or identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) ". Thank you
$query = "SELECT * FROM employees ";
$query = mysqli_query($connect,$query);
while($row= mysqli_fetch_array($query)) {
echo '<div>';
echo "<a href='profile.php?userId = <?php echo $row['id'];?>'>"; // error is here.. it should print out the user id in the url
echo $row['firstName'] . " ". " ".$row['lastName'];
echo '</a>';
echo '</div>';
}
2 Answers
Spenser Hale
20,915 PointsHello Abe Layee,
Your error is because you have a string syntax error. See PHP Strings Documentation
TLDR:
It appears "<?php echo $row['id'];?>" is copy from another project/ stack overflow without trying to understand what it does or how it works.
Issues:
- Your query string cannot have spaces.
- before closing the string you have <?php echo, which should not be in the string.
- You cannot execute php within a string
Your code:
<?php echo "<a href='profile.php?userId = <?php echo $row['id'];?>'>";
Quick fix:
<?php echo "<a href='profile.php?userId={$row['id']}>";
Recommended Solution:
I would recommend using http_build_query since it will help you escape values and allows you to build complex query strings with ease. It is more readable and performant to echo once, so I combined statements and renamed variables to better describe their use.
<?php
while ($row = mysqli_fetch_array($query)) {
$href = 'profile.php?'.http_build_query([
'userId' => $row['id'],
]);
$anchorText = $row['firstName'].' '.$row['lastName'];
echo "<div><a href=\"{$href}\">{$anchorText}</a></div>";
}
Abe Layee
8,378 PointsI got it... thank