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PHP PHP Functions Introducing Functions PHP Function Arguments

lewis tibbott
lewis tibbott
1,754 Points
Posted by lewis tibbott
lewis tibbott
1,754 Points

Not the same output

<?php

function hello($arr) {

if (is_array($arr)) {
    foreach ($arr as $name){
        echo "Hello $name <br>";
    }
} else {
    echo "Hello";
}

}

$names = array("name1, name2, name3"); hello($names); ?>

When I run my code the output is hello name1 name2 name3 when it should be hello name1 hello name2 hello name3

I don't understand why its working like this, could someone please explain?

1 Answer

Riku S.
Riku S.
11,322 Points

The array items are strings and each one of them has to wrapped inside quotes, now you have all of them wrapped in one pair of quotes.

// Your code
$names = array("name1, name2, name3");

// Change it to this
$names = array("name1", "name2", "name3");