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Start your free trialRafael Maida
2,307 Pointsodd numbers
i am looking to create a fucntion that determines if a number is even/odd
def is_odd (num):
(float(num) % 2) > 0
1 Answer
Steven Parker
231,248 PointsYou're really close! You just need a "return" keyword to give your result back to the caller.
Also, while it won't affect passing the challenge, you don't need to convert the number with "float".