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PHP PHP Basics Daily Exercise Program Conditionals

PHP challenge

Check if each student has a GPA of 4.0. If the student has a GPA of 4.0, use the student's name variable to display "NAME made the Honor Roll". If not, use the variable to display "NAME has a GPA of GPA". This is the task. When I write the if statemant, it displays: "You need to check if the $studentOneGPA is 4.0". My code is in the attachment of this post.

index.php
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment

if($studentOneGPA==4.0)
{
  echo $studentOneName. ' made the Honor Roll.';  
}
  else
  {
  echo $studentOneName. ' has a GPA of '.$studentOneGPA;
  }
if($studentTwoGPA==4.0)
{
  echo $studentTwoName. ' made the Honor Roll.';  
}
  else
  {  
  echo $studentTwoName. ' has a GPA of '.$studentTwoGPA;
  }
?>

1 Answer

Jonathan Grieve
MOD
Jonathan Grieve
Treehouse Moderator 91,253 Points

Hi Lazar.

You were very very close. It looks like the confusion was with the specific output of the string the challenge was looking for. If you look at the preview in the code challenge before you submit, you can see clues as to how the page will display. Try adding a space in the first block of each if statement.

So I went ahead and tried the challenge and this should pass.

<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment

if($studentOneGPA==4.0) {
  echo $studentOneName. ' made the Honor Roll. ';  
} else {
  echo $studentOneName. ' has a GPA of '.$studentOneGPA . '.';
  }

if($studentTwoGPA==4.0) {
  echo $studentTwoName. ' made the Honor Roll. ';  
} else {  
  echo $studentTwoName. ' has a GPA of '.$studentTwoGPA . '.';
  }
?>

That worked! Thank you Jonathan, you saved me a lot of time!