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Ioan Ionkov
Courses Plus Student 6,921 PointsPHP method issue
Hello!
I am not able to properly solve this task, I have tried applying the method several ways, but it seems that I don't understand it well enough, hence, please help me grasp the concept and solve this task
<?php
include 'class.palprimechecker.php';
$checker = new PalprimeChecker;
$checker -> number = 17;
echo "The number " . $checker->number ;
if isPalprime($checker->number){
echo "is" . ;
else{
echo "is not" . ;
}
echo " a palprime.";
?>
1 Answer
Benjamin Larson
34,055 PointsHi Ioan -
The challenge makes a note that the isPalprime() function doesn't accept any arguments. Therefore, you should call it like this:
$checker->isPalprime()
Try adding that inside your conditional logic.
Ioan Ionkov
Courses Plus Student 6,921 PointsIoan Ionkov
Courses Plus Student 6,921 PointsThis is the task's condition: PalprimeChecker objects have a method called isPalprime(). This method does not receive any arguments. It returns true if the number property contains a palprime, and it returns false if the number property does not contain a palprime. (Tip: 17 is not a palprime.) Turn the second echo statement into a conditional that displays "is" or "is not" appropriately. The conditional should call the isPalprime method of the $checker object. If the isPalprime method returns true, then echo "is"; otherwise, echo "is not".