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Start your free trialMarcus Yang
7,476 PointsPython basic
This challenge is similar to an earlier one. Remember, though, I want you to practice! You'll probably want to use try and except on this one. You might have to not use the else block, though. Write a function named squared that takes a single argument. If the argument can be converted into an integer, convert it and return the square of the number (num ** 2 or num * num). If the argument cannot be turned into an integer (maybe it's a string of non-numbers?), return the argument multiplied by its length. Look in the file for examples. I think that my code is right. What's wrong with it? Please help me explain it. I will appreciate it.
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
try:
if num == int(num):
return num * num
except:
return num * len(num)
print(squared("tim"))
1 Answer
Steven Parker
231,271 PointsThis seems to be a duplicate of your previous question.
Your program converts the argument to an integer, but only to compare it with the unconverted version. The comparison isn't actually needed, plus the converted value isn't being saved so it can be squared.
Also, you only need to define the function. You don't need to call it yourself, and you don't need to "print" anything.