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2,355 PointsRandom Number
I am having issues getting this block of code to enter the first portion of the conditional statement. Even when entering 2 if runs the else portion.
let userGuess = prompt('Please provide a number?'); //Collect input from a user if(userGuess === 2){ userGuess =+ +userGuess; // convert input to a number userGuess =+ Math.random() + userGuess; //Use Math.random() and the user's number to generate a random number console.log(userGuess); }else{ console.log('You did not provide a number'); console.log(userGuess); console.log(typeof userGuess); }
1 Answer
Steven Parker
231,248 PointsThe "prompt" function always returns a string, and because of the type-sensitive comparison (===) the input can never match the number 2.
An easy fix would be to compare with the string "2" instead, or use the normal comparison operator (==).