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JavaScript JavaScript Loops Working with 'for' Loops The Refactor Challenge – Duplicate Code

Posted by Seth Lewis
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Seth Lewis
Full Stack JavaScript Techdegree Graduate 18,191 Points

rgb parens

The code below is refactored to call the randomValue() function on rgb which is assigned to const color.

Why does rgb require a parens () in order for randomValue() to run? (i. e. rgb( function calls() )

function randomRGB() { const color = rgb(${randomValue()}, ${randomValue()}, ${randomValue()}); return color; }

1 Answer

Steven Parker
Steven Parker
231,248 Points
Steven Parker
Steven Parker
231,248 Points

To invoke any function (make it run) you place parentheses after its name, whether or not you pass it any arguments inside the parentheses.

This rule is the same in JavaScript and CSS.

Seth Lewis
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Seth Lewis
Full Stack JavaScript Techdegree Graduate 18,191 Points

Steve,

Thanks for taking a look at this. To clarify: I was asking about the rgb assigned to const color. Is that what you were addressing? I understand that the function randomRGB requires parens to invoke. I don't see where 'rgb' is a function in the code.

Is that making more sense? Sorry if I'm not being terribly clear. Thanks!

Steven Parker
Steven Parker
231,248 Points
Steven Parker
Steven Parker
231,248 Points

The "rgb" used here is a CSS function . It's a built-in standard in the browser. But CSS functions use parentheses in the same way as JavaScript functions. Plus, in this case they also contain 3 arguments (the color values) being passed to the function.

Seth Lewis
.a{fill-rule:evenodd;}techdegree seal-36
Seth Lewis
Full Stack JavaScript Techdegree Graduate 18,191 Points

Ah - I see. I don't have much experience with CSS and, as you noted, it was clear to me that I was passing args into the parens. I had heard that CSS utilizes functions but I haven't done that myself. Thank you for clarifying!