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Start your free trialJulian Newman
67 PointsShopping-List-App pt 2
Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".
def loopy(items):
# Code goes here
if item in items:
if item == "a":
continue
print(item)
1 Answer
Steven Parker
231,271 PointsYou don't want to check if the entire current item is "a", only the "character at index 0 of the current item". To apply an index, place braces ("[]") after the name with the index number inside them.