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WordPress How to Build a WordPress Plugin How WordPress Plugins Work Examples of WordPress Actions and Filters

Posted by Bratimir Timotijevic
Bratimir Timotijevic
1,682 Points

Should we put $content .=$social_content; on line 25 instead of $content .=$new_content; ?

Is there an error in a code example of how to append sharing content?

4 Answers

weal
PLUS
weal
Courses Plus Student 4,375 Points
weal
weal
Courses Plus Student 4,375 Points

I see this is an old question, but this small error still exists in the project files.
Please see 6:59 in the video.
$social_content is the variable with the content to add, but $new_content is used, which isn't defined.

Zac Gordon
STAFF
Zac Gordon
Treehouse Guest Teacher
Zac Gordon
Zac Gordon
Treehouse Guest Teacher

Hi, I don't think so, are you noticing an error?

Gerson Koenig
Gerson Koenig
8,061 Points
Gerson Koenig
Gerson Koenig
8,061 Points

There's no error, but once you add a plugin header and activate the code on WP 4.2.2, the plugin has no effect until you match up the variable names:

            $social_content = 'Insert in the social sharing code here';
            $content .= $social_content;
liktid
liktid
6,387 Points
liktid
liktid
6,387 Points

shouldnt this error be fixed after this long time? or when its not an error explained?

michaeldavies3
michaeldavies3
23,004 Points

Just seen this, totally agree - this is an error surely? Concatenating $content with an empty $new_content would do nothing, and $social_content is left alone.

I'm assuming this is a couple of years old now, but this should be fixed, even just in the project download files with a quick note commented out in the PHP.