Solution Allows User Input of Zero and Gives Feedback as User Inputs Data (Asks for High Number First)

Question

const inputHigh = prompt("Let's generate a random number. What do you want the largest number that can be generated to be?");

const numberHigh = parseInt(inputHigh);

if (!numberHigh && numberHigh !== +0) {
  alert('You need to provide a high number. Try again.'); // if numberHigh is false (no input or value is a string) and isn't zero, the program displays an alert and the program ends.*/
} else {

  const inputLow = prompt("What do you want the lowest number that can be generated to be?");

  const numberLow = parseInt(inputLow);

  if (numberLow || numberLow === +0) { // JavaScript treats a zero without a unary plus operator as a false value, so I included the numeric zero value (+0) in the condition using a logical OR operator.
    const randomNumber = Math.floor( Math.random() * (numberHigh - numberLow + 1) ) + numberLow;
    alert(`The number generated from ${numberLow.toLocaleString()} to ${numberHigh.toLocaleString()} is ${randomNumber.toLocaleString()}`);
   } else {
     alert("You need to provide a low number. Please try again.");
   }}

Answer 1 · 2025-01-31T14:02:52Z

January 31, 2025 2:02pm

It's normal for a 0 numeric value or empty string to evaluate as a false when taken as a Boolean, you don't need a sign when comparing a 0 to a number.

But to use logic to combine multiple comparisons, each comparison must be complete. So for your code to work as you intended, do this:

if (numberLow == 0 || numberLow == 0)   // the === comparator will also work

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isaacismyname

isaacismyname

Solution Allows User Input of Zero and Gives Feedback as User Inputs Data (Asks for High Number First)

1 Answer

Steven Parker

Steven Parker