squared.py

Question

Hi guys,
really struggling here... I know this should be easy but the challenge wont pass me. It runs and prints the correct number in the Workspace:
def square(number):
    result = number * number 
    print(result)
square(3)       
Any help is sincerely appreciated!!!!
```squaring.py
def square(number):
    result = number * number 
    return result
square(3)       
print(result)
```

behar · Accepted Answer

Hey Stuart! Because of the concept of scope, outside the 'square' function the variable 'result' actually does not exist, therefor you will get a compiler error.
Also there is something import you seem to have misunderstood, when you call a function like you did in when you said:
python
square(3)

The result from this is not saved inside the variable 'result', and cannot be used later outside the function. Instead the result is imidiately returned from the function.
Therefor, simply say:
python
print(square(3))

Also two ways that will make your code smaller is to, instead of saving the square of the number into a variable called result, why don't you just imidiately return the answer:
python
def square(number):
    return number * number

And finally there is an operator for squaring, instead of saying num * num, you can say num ** 2.
Hope this helps, and good luck!

Stuart Main · Answer

Thanks again behar!

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squared.py

2 Answers

behar

behar

Stuart Main

Stuart Main

behar

behar

Stuart Main

Stuart Main