Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialhussein hammoud
8,543 PointsThe message in the final echo command only makes sense if your favorite flavor is the same as Hal's. Add a conditional a
The message in the final echo command only makes sense if your favorite flavor is the same as Hal's. Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough." (Remember to choose carefully between using a single equal sign and a double equal sign in the check.) Preview the code and, if you have a different flavor, make sure the message disappear
<?php
$flavor = "Chocolate";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
echo "<p>Hal's favorite flavor is $, also!</p>";
?>
5 Answers
JULIO ANDRES SEGOVIA
9,234 PointsHello, This works for me ;) You must not display any message.
<?php
$flavor = "Chocolate";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if($flavor == "cookie dough"){
echo "<p>Hal's favorite flavor is $flavor, also!</p>";
}
else{
echo "";
}
?>
Matthew Bilz
15,829 PointsHi there,
I believe they're looking for an if/else conditional statement. For instance:
echo ".</p>";
if($flavor == "cookie dough") {
echo "<p>Hal's favorite flavor is also cookie dough!</p>";
} else {
echo "<p>Too bad Hal doesn't love $flavor like I do!</p>";
}
Matthew Morales
36,545 PointsYou were missing the flavor part in the final line
<?php
$flavor = "Chocolate";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
echo "<p>Hal's favorite flavor is $flavor, also!</p>";
?>
Katiuska Alicea de Leon
10,341 PointsI did this exact thing and I got "Bummer: The ice cream flavors do not match, yet I still see a message that they do."
Michael Hicks
24,208 Points<?php
$flavor = "moose tracks";
echo "<p>Your favorite flavor of ice cream is <?php echo $flavor ?>";
echo "vanilla";
echo ".</p>";
if ( $flavor == "cookie dough" ) {
echo "<p>Hal's favorite flavor is cookie dough, also!</p>";
}
?>
Here's my code. It worked, but why is 'echo "vanilla";' even included? I feel like its a red herring. The last part of this task was a little confusing and less practical. Am I just whining or does this make sense?
Katiuska Alicea de Leon
10,341 PointsYou have to create another variable that has the value for Hal's favorite ice cream flavor and use it for the "elseif" statement.