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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Random Number Challenge, Part II Solution

Seokhyun Wie
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Seokhyun Wie
Full Stack JavaScript Techdegree Graduate 21,606 Points
Posted by Seokhyun Wie
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Seokhyun Wie
Full Stack JavaScript Techdegree Graduate 21,606 Points

Using 'else' clause instead of directly writing 'return' clause

Hi guys, I used a little bit of different approach from the solution that is mentioned in the video.

function randomNumber(lower, upper) {
    if (isNaN(lower) || isNaN(upper)) {
        throw new Error('error message');
    } else {
        return Math.floor(Math.random() * (upper - lower + 1) + lower);
    }
}
console.log(randomNumber('nine', 1000));

Is there any problem with this approach? If there is, please let me know, or if not, also please let me know the pros and cons of it. Thank you so much!

2 Answers

Dmitry Polyakov
Dmitry Polyakov
4,989 Points
Dmitry Polyakov
Dmitry Polyakov
4,989 Points

These two functions will produce the same result

function randomNumber(lower, upper) {

if (isNaN(lower) || isNaN(upper)) {

    throw new Error('error message');

} else {

    return Math.floor(Math.random() * (upper - lower + 1) + lower);

}

}

console.log(randomNumber('nine', 1000));

function randomNumber(lower, upper) {

if (isNaN(lower) || isNaN(upper)) {

    throw new Error('error message');

} 

 return Math.floor(Math.random() * (upper - lower + 1) + lower);

}

console.log(randomNumber('nine', 1000));

Steven Parker
Steven Parker
231,271 Points
Steven Parker
Steven Parker
231,271 Points

Adding the "else" won't cause any difference in behavior; but it's not needed, since when the "if" test is true, the "throw" will stop the function. So any code after the conditional block can only run in the "else" condition.