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JavaScript AJAX Basics Programming AJAX Check for the correct ready state

Posted by Alexandru Pescaru
Alexandru Pescaru
6,410 Points

what am i doing here wrong...

so can anyone help me with the correct code here please. thx

app.js 
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {

};
xhr.open('GET', 'sidebar.html');
xhr.send();
xhr.onreadystatechange = function () {
      if (xhr.readyState === 4) {
        document.getElementById('ajax').innerHTML = xhr.responseText;      
      }
    };

 xhr.open('GET', 'sidebar.html');
xhr.send();
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>