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Start your free trialRobin Prak
586 PointsWhy doesn't get this the words with four or more characters? (using '\w{4,}' in this instance
Using regular expressions. Could it be that the input variable does net get parsed like this?
import re
# EXAMPLE:
# >>> find_words(4, "dog, cat, baby, balloon, me")
# ['baby', 'balloon']
def find_words(ncount, nstring):
fmatch = re.findall(r"\w{ncount,}", nstring);
return fmatch
2 Answers
William Gough
18,852 PointsI used the code posted above:
def find_words(ncount, nstring):
fmatch = re.findall(r"\w{" + ncount + r",}", nstring);
return fmatch
It gave me an error saying: Cannot convert integer to string, this solution worked for me:
def find_words(ncount, nstring):
fmatch = re.findall(r"\w{" + str(ncount) + r",}", nstring);
return fmatch
Iain Simmons
Treehouse Moderator 32,305 PointsCorrect, the parameter ncount
is being treated as a literal string within the raw text string used for the regex.
You have a couple of options, first, you can concatenate the variable in between some strings to build the regex:
def find_words(ncount, nstring):
fmatch = re.findall(r"\w{" + ncount + r",}", nstring);
return fmatch
Second, you can use .format()
and escape the curly braces (this looks a bit insane):
def find_words(ncount, nstring):
fmatch = re.findall(r"\w{{{},}}".format(ncount), nstring);
return fmatch
In a string where you're using .format()
, you use double curly braces to print a literal curly brace:
print("A string with {{curly braces}}".format())
a_variable = "a variable"
print("A string with {{curly braces and {} too}}".format(a_variable))
The above will print:
A string with {curly braces}
A string with {curly braces and a variable too}
Iain Simmons
Treehouse Moderator 32,305 PointsIain Simmons
Treehouse Moderator 32,305 PointsAhh yes, forgot about the type. Good catch.