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PHP Build a Basic PHP Website (2018) Adding a Basic Form Checking the Request Method

Modure Rares
PLUS
Modure Rares
Courses Plus Student 9,041 Points
Posted by Modure Rares
Modure Rares
Courses Plus Student 9,041 Points

Why i get the notice Undefined index status????

I hace this php code but it triggesr an notice and the ?status is not working. When i ckick the submit button it should only show the thanking text, instead it shows file not found error please help me

if($_SERVER["REQUEST_METHOD"] == "POST") {

        $name = $_POST["name"];
        $email = $_POST["email"];
        $details = $_POST["suggestion"];

        echo "<pre>";
        $email_body = "";
        $email_body .= "Name: " . $name . "\n";
        $email_body .= "Email: ". $email . "\n";
        $email_body .= "Details: " . $details ."\n"; #this represents a linebreak 
        echo $email_body;
        echo "</pre>";

        // EMAIL SENDING CODE HERE 

        //**********************************************

        header("location:suggest.php$stage=thanks");
    }

    $pageTitle = "Suggest a Improvement";
    $section = "suggest";

    include("include/header.php");
 ?>


    <form id="suggestion" method="post" action="suggest.php">

        <h1 id="suggest-title">Suggest an Improvement</h1>

        <?php if($_GET["stage"] == "thanks" && isset($_GET["stage"])) {

                echo "<div id='thanks'><h1> Thank You! </h1></div>";
            } else {?>
        <fieldset>

            <label for="name">Name:</label>
            <input id="name" type="text" name="name">

            <label for="email">Email:</label>
            <input type="email" name="email" id="email">

        </fieldset>

        <fieldset>

            <label for="suggestion">Suggest:</label>
            <textarea name="suggestion" id="user_ideea">your idea...</textarea>

        </fieldset>

        <fieldset>

            <input type="submit" value="Send">

        </fieldset>
    </form>
    <?php } ?>
 </body>
 </html>

2 Answers

Colin V
Colin V
5,784 Points
Colin V
Colin V
5,784 Points

It looks like to me the problem here is this line:

header("location:suggest.php$stage=thanks");

In this case, there are 2 problems: $ is in place of ? and "stage" is in place of "status".

So think of the header("location:"); function like you would an url, when a get query is made it uses "?{variable}=" instead of "${variable} =" like in PHP.

So what you'd like here is to have "?status=" as the variable the file is looking for is status, and ? denotes the start of variables.

To go further, in an url, you want to separate variables with an & symbol (although since there is only one variable being passed along in this case, the status variable, we don't need to worry about that).

Madhuri Charugundla
Madhuri Charugundla
2,383 Points
Madhuri Charugundla
Madhuri Charugundla
2,383 Points

header("location:suggest.php$stage=thanks") -- Problem is with this line. Use ? instead $.